3x^2-12.5x+12=0

Solution for 3x^2-12.5x+12=0 equation:

3x^2-12.5x+12=0

a = 3; b = -12.5; c = +12;
Δ = b2-4ac
Δ = -12.52-4·3·12
Δ = 12.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12.5)-\sqrt{12.25}}{2*3}=\frac{12.5-\sqrt{12.25}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12.5)+\sqrt{12.25}}{2*3}=\frac{12.5+\sqrt{12.25}}{6}
$